substitution using perl -pi -e

s_gaurav1091 has asked for the wisdom of the Perl Monks concerning the following question:

Hi monks , I am using a command to substitute the contents of my file my file contains a line site.type=standby and i want to change that line to site.type=production.I am getting errors in the code.I am wriiting the code as well as the error for your refrence.Please suggest something

perl -pi -e 's/site.type=standby/site.type=production/gei ' /usr/local
+/jboss/conf/environment.properties
[download]

It is giving an error that can't modify concatenation (.) or string in scalar assignment at -e line 1, near "production }"

Comment on substitution using perl -pi -e Download Code

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Re: substitution using perl -pi -e by Corion (Patriarch) on Nov 08, 2005 at 08:32 UTC
Why are you using the `/e` switch? This makes Perl think that you want to see the "replacement" part of `s///` as a Perl expression. You likely want: `perl -pi.bak -e 's/site.type=standby/site.type=production/gi' /usr/loc +al/jboss/conf/environment.properties` [download]	[reply] [d/l]
Re: substitution using perl -pi -e by b10m (Vicar) on Nov 08, 2005 at 10:59 UTC
Or just "`sed -i 's/site.type=standby/site.type=production/gi' /.../environment.properties`" ;-) -- b10m All code is usually tested, but rarely trusted.	[reply] [d/l]
Re: substitution using perl -pi -e by blazar (Canon) on Nov 08, 2005 at 10:37 UTC
Indeed `/e` executes in the replacement part of the `s///` operator. Do you happen to know that `site.type=production;` [download] is valid Perl (5, that is!) code? How so?!? Incidentally you may use `s/(?<=site.type=)standby/production/gi` [download] instead.	[reply] [d/l] [select]
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