in reply to Reference Question

    push( @docs, \@doc );

You need push( @docs, [ @doc ] );. The reason is that if you use a backslash, you are taking a reference to the same variable, which contains differents things each time but the reference "points to" the same location in memory. Using square brackets, you create a new reference each time. That's the difference.

Update: To make things clearer, look at this program and its output:

use Data::Dumper; my (@c, @d); foreach (1..3) { @c[0..4] = (rand) x 2; push @d, \@c; } print Dumper \@d; @d=(); ## reset @d foreach (1..3) { @c[0..4] = (rand) x 2; push @d, [@c]; } print Dumper \@d; __END__ $VAR1 = [ [ '0.566846394018409', '0.566846394018409' ], $VAR1->[0], $VAR1->[0] ]; $VAR1 = [ [ '0.872105763616624', '0.872105763616624' ], [ '0.0550789852978433', '0.0550789852978433' ], [ '0.130973801235072', '0.130973801235072' ] ];

The first time, @d is populated with references to the same information (Data::Dumper shows $VAR1->[0] instead of repeating it). The second example shows different numbers because [ ] create different references each time.

--
David Serrano

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Re^2: Reference Question
by GrandFather (Saint) on Aug 03, 2006 at 21:49 UTC

    Actually you create a copy each time with the [], and push a reference to the copy.

    In the original code the push was creating a new reference each time - to the same instance.


    DWIM is Perl's answer to Gödel
Re^2: Reference Question
by caseydentinger (Novice) on Aug 03, 2006 at 21:48 UTC
    Perfect! Thanks a ton. For my own edification, do the square brackets actually copy the array *and* make a reference to it in one fell swoop?

      The [] makes an anonymous copy of the array and in effect returns an reference to it. {} can be used in similar fashion to create an anonymous copy of a hash.


      DWIM is Perl's answer to Gödel