Re: Quick Regex Question

s/([^\w-])/'%'.unpack("H*", $1)/eg;    # %5e%25%40%7cCaD5H
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See perlre, pack and unpack. If you need to use another character besides '%', go for it.

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Re: Re: Quick Regex Question by Anonymous Monk on Feb 08, 2001 at 00:19 UTC
Thanks. I got it working both ways.. works great. What does the e do? ( .. ("H*", $1)/eg; ) I didn't see it in perlre. tia	[reply]
Re: Re: Re: Quick Regex Question by chipmunk (Parson) on Feb 08, 2001 at 00:32 UTC
It turns out that /e is not documented in perlre because /e does not affect the regular expression. Instead, /e is documented in perlop, in the documentation for s/// (near the bottom).	[reply]
Re: Re: Re: Quick Regex Question by Fastolfe (Vicar) on Feb 08, 2001 at 00:23 UTC
Odd; I can't find it documented either. Its purpose is to tell Perl to evaluate the right-hand-side of a substitution, instead of just using it as-is. This lets you put code in the right-hand-side of a substitution instead of just text.	[reply]