Re^2: Quick Regex Question

Replies are listed 'Best First'.
Re^3: Quick Regex Question by Corion (Patriarch) on May 07, 2007 at 20:24 UTC
A better post would have been then: `$dated = '03/30/2007'; if ($dated =~ m/^[0-3][0-9]\/[0-1][0-9]\/[1-2][0-9][0-9][0-9]$/) { } else { #User entered an invaild date. $passfail = 0; $errmsg = 'Unable to use date format. Please use "MM/DD/YYYY" or MM-DD +-YYYY for the Date Delivered Field'; $errtitle = 'Validation Error'; $seconds = 7; }` [download] This fails, because your second segment does only allow for `00` to `19` and never for `30`, which seems sensible if you want to validate dates in the format DD/MM/YYYY as you say. Your error message doesn't match that, as there you claim to match MM/DD/YYYY...	[reply] [d/l] [select]
Re^3: Quick Regex Question by suaveant (Parson) on May 07, 2007 at 20:30 UTC
Well.. that is easy... your dates are DD/MM/YYYY bust your regexp is MM/DD/YYYY first section matches 00 to 19, second matches 00 to 39, so many values you pass would fail... `/^(?:[0-3]\d\/[01]\d\/(?:19\|20)\d\d)?$/` [download] will do it, but as other people have said, there are better ways. - Ant - Some of my best work - (1 2 3)	[reply] [d/l]
Re^4: Quick Regex Question by Trihedralguy (Pilgrim) on May 07, 2007 at 20:47 UTC
I need to do dd/mm/yyyy - I accidentally ignored my mistake within my error message. How would I switch your regex around to use dd/mm/yyyy instead of mm/dd/yyyy	[reply]
Re^5: Quick Regex Question by suaveant (Parson) on May 07, 2007 at 21:40 UTC
Just switch before and after the first / `/^(?:[01]\d\/[0-3]\d\/(?:19\|20)\d\d)?$/` [download] But the test data you said you used was 03/30/2007 which is MM/DD/YYYY - Ant - Some of my best work - (1 2 3)	[reply] [d/l]