Re^3: Quick Regex Question

Well.. that is easy... your dates are DD/MM/YYYY bust your regexp is MM/DD/YYYY first section matches 00 to 19, second matches 00 to 39, so many values you pass would fail...

/^(?:[0-3]\d\/[01]\d\/(?:19|20)\d\d)?$/
[download]

will do it, but as other people have said, there are better ways.

- Ant
- Some of my best work - (1 2 3)

Comment on Re^3: Quick Regex Question Download Code

Replies are listed 'Best First'.
Re^4: Quick Regex Question by Trihedralguy (Pilgrim) on May 07, 2007 at 20:47 UTC
I need to do dd/mm/yyyy - I accidentally ignored my mistake within my error message. How would I switch your regex around to use dd/mm/yyyy instead of mm/dd/yyyy	[reply]
Re^5: Quick Regex Question by suaveant (Parson) on May 07, 2007 at 21:40 UTC
Just switch before and after the first / `/^(?:[01]\d\/[0-3]\d\/(?:19\|20)\d\d)?$/` [download] But the test data you said you used was 03/30/2007 which is MM/DD/YYYY - Ant - Some of my best work - (1 2 3)	[reply] [d/l]