Re: calling subs using references.

Since the dereferencing chain is ambiguous, you have to resolve it yourself:

my $word = $rf->{test1};
$tes->$word();
[download]

--shmem

_($_=" "x(1<<5)."?\n".q·/)Oo.  G°\        /
                              /\_¯/(q    /
----------------------------  \__(m.====·.(_("always off the crowd"))."·
");sub _{s./.($e="'Itrs `mnsgdq Gdbj O`qkdq")=~y/"-y/#-z/;$e.e && print}

Comment on Re: calling subs using references. Download Code

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Re^2: calling subs using references. by blazar (Canon) on May 22, 2007 at 12:05 UTC
Since the dereferencing chain is ambiguous, you have to resolve it yourself: `my $word = $rf->{test1}; $tes->$word();` [download] Well, I asked something very similar some time ago. A particularly interesting reply deals both with symbolic and real references: AIUI `$tes->${\$rf->{test1}}();` [download] should work. I haven't tested it though, so caveat. Even if it works, it's certainly clumsy and not very friendly to people seeing it.	[reply] [d/l] [select]

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Re^2: calling subs using references.
by blazar (Canon) on May 22, 2007 at 12:05 UTC

Since the dereferencing chain is ambiguous, you have to resolve it yourself:

my $word = $rf->{test1}; $tes->$word();
[download]

Well, I asked something very similar some time ago. A particularly interesting reply deals both with symbolic and real references: AIUI

$tes->${\$rf->{test1}}();
[download]

should work. I haven't tested it though, so caveat. Even if it works, it's certainly clumsy and not very friendly to people seeing it.

[reply]
[d/l]
[select]