in reply to Re^3: why does push not default to $_?
in thread why does push not default to $_?

hmm, I thought it may be a compiler limitation on the first argument, but split defaults to $_ on its second argument, (' ' on first one)

I think there is no logical reason!

Cheers Rolf

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Re^5: why does push not default to $_?
by ikegami (Patriarch) on Dec 05, 2008 at 02:36 UTC
    Ok, seems like it's proven there's no technical reason it can't be done.
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