Re^3: why does push not default to $

Yeah, I already noticed and updated my node.

The only possible reason I could see if an undue burden on the parser, since it would be the first function to default the second argument. You could send a perl (wishlist) bug report?

Comment on Re^3: why does push not default to $_?

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Re^4: why does push not default to $_? by LanX (Saint) on Dec 04, 2008 at 23:25 UTC
hmm, I thought it may be a compiler limitation on the first argument, but `split` defaults to $_ on its second argument, (' ' on first one) I think there is no logical reason! Cheers Rolf	[reply] [d/l]
Re^5: why does push not default to $_? by ikegami (Patriarch) on Dec 05, 2008 at 02:36 UTC
Ok, seems like it's proven there's no technical reason it can't be done.	[reply]