in reply to Re: why does push not default to $_?
in thread why does push not default to $_?

Good argument, but whats the difference to
print @b;
if @b is empty? It doesn't print $_
for (1..13) { print @b; }
Furthermore there is no error with:
push @a, @b;
but you get a warning with
push @a;
so perl can distinguish between missing parameters and empty parameters...

Cheers Rolf

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Re^3: why does push not default to $_?
by ikegami (Patriarch) on Dec 04, 2008 at 21:48 UTC

    Yeah, I already noticed and updated my node.

    The only possible reason I could see if an undue burden on the parser, since it would be the first function to default the second argument. You could send a perl (wishlist) bug report?

      hmm, I thought it may be a compiler limitation on the first argument, but split defaults to $_ on its second argument, (' ' on first one)

      I think there is no logical reason!

      Cheers Rolf

        Ok, seems like it's proven there's no technical reason it can't be done.