Re^3: How to call a sub reff from a hash

Because you have no scalar $Procedures declared (you have a hash %Procedures, but that's something completely different).

The cake is a lie.
The cake is a lie.
The cake is a lie.

Comment on Re^3: How to call a sub reff from a hash Select or Download Code

Replies are listed 'Best First'.
Re^4: How to call a sub reff from a hash by NateTut (Deacon) on Dec 15, 2008 at 22:12 UTC
Yes, but I'm trying to access an element of that hash.	[reply] [d/l]
Re^5: How to call a sub reff from a hash by ikegami (Patriarch) on Dec 15, 2008 at 22:17 UTC
Your wrong code: `$Procedures->{$Procedure}($Parameter); ^^^^^^^^^^^ Not a hash. Undeclared and uninitialized scalar.` [download] The correct code: `$Procedures{$Procedure}->($Parameter); ^^^^^^^^^^^^^^^^^^^^^^^ Element of a hash` [download]	[reply] [d/l] [select]
A reply falls below the community's threshold of quality. You may see it by logging in.
Re^5: How to call a sub reff from a hash by Fletch (Bishop) on Dec 15, 2008 at 22:16 UTC
Then you want to re-read perldata and perlreftut because `$foo->{'bar'}` has nothing to do with trying to get at `$foo{'bar'}`. The cake is a lie. The cake is a lie. The cake is a lie.	[reply] [d/l] [select]
Re^6: How to call a sub reff from a hash by NateTut (Deacon) on Dec 15, 2008 at 22:19 UTC
Originally I had: `&$Procedures{$Procedure}($Parameter);` but that gives me the same error.	[reply] [d/l] [select]