Re: How regex works here?

In the first regex you are matching only the "B6y green" and you are replacing that again with "B6y green". So the $lines is same as it is

In the second regex you are matching "B6y green" and the remaining string and you are replacing that with "B6y green". So the $lines has only the matched pattern.

--Lakshmanan G.

The great pleasure in my life is doing what people say you cannot do.

Comment on Re: How regex works here?

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Re^2: How regex works here? by nagalenoj (Friar) on Apr 08, 2009 at 05:38 UTC
yeeeah..! Fine.. I understood., So the problem is not with the matching and with the substitution. Thanks..!	[reply]
Re^3: How regex works here? by bart (Canon) on Apr 08, 2009 at 09:01 UTC
Yes. There's no need at all to change the original string to extract the data you want. All you need is to match it. `if($line =~ /^(\S+\s+\S+)/) { $match = $1; }` [download] or even simpler: `($match) = $line =~ /^(\S+\s+\S+)/;` [download] Note that for the latter, the assignment must be in list context, not scalar context; that's what the parens around the variable on the left hand side are for.	[reply] [d/l] [select]