Re^2: How regex works here?

yeeeah..! Fine.. I understood.,

So the problem is not with the matching and with the substitution.

Thanks..!

Comment on Re^2: How regex works here?

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Re^3: How regex works here? by bart (Canon) on Apr 08, 2009 at 09:01 UTC
Yes. There's no need at all to change the original string to extract the data you want. All you need is to match it. `if($line =~ /^(\S+\s+\S+)/) { $match = $1; }` [download] or even simpler: `($match) = $line =~ /^(\S+\s+\S+)/;` [download] Note that for the latter, the assignment must be in list context, not scalar context; that's what the parens around the variable on the left hand side are for.	[reply] [d/l] [select]

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Re^3: How regex works here?
by bart (Canon) on Apr 08, 2009 at 09:01 UTC

There's no need at all to change the original string to extract the data you want. All you need is to match it.

if($line =~ /^(\S+\s+\S+)/) {
    $match = $1;
}
[download]

($match) = $line =~ /^(\S+\s+\S+)/;
[download]