in reply to Local for lexicals
So in analogy to ruby
lamb = lambda { |x, y, z| z = x + y}
you want to write
$lamb = lambda ($x,$y,$z) => { $z = $x + $y }
such that $lamb->(1,2,$a) sets $a to 3 ???
Cheers Rolf
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Re^2: Local for lexicals
by JadeNB (Chaplain) on Aug 10, 2009 at 23:03 UTC | |
by LanX (Saint) on Aug 10, 2009 at 23:37 UTC | |
by JadeNB (Chaplain) on Aug 11, 2009 at 03:28 UTC | |
by BrowserUk (Patriarch) on Aug 11, 2009 at 04:39 UTC | |
by JadeNB (Chaplain) on Aug 12, 2009 at 19:17 UTC | |
by LanX (Saint) on Aug 11, 2009 at 13:18 UTC | |
by JavaFan (Canon) on Aug 11, 2009 at 13:39 UTC | |
by JavaFan (Canon) on Aug 11, 2009 at 10:06 UTC | |
by ikegami (Patriarch) on Aug 12, 2009 at 21:00 UTC |