in reply to Re^3: Referencing in Function not working correctly.
in thread Referencing in Function not working correctly.

my @x = ("z", "y", "z");
@x = ();

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Doesn't the @x get initialize here? If I want to reuse @x what do I do to initialize, is there another way?

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Re^5: Referencing in Function not working correctly.
by jwkrahn (Abbot) on Apr 02, 2010 at 19:38 UTC

    Yes @x gets initialized there, but ("z", "y", "z") is different than (), and my @x is different than my ( @x, @y, @z ).

    What do you think my ( @x, @y, @z ) = ("z", "y", "z"); does?

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      I am sorry I have no idea what that does. Please explain. My guess is @x[0]=z, @y[0]=y and @z[0]=z.

      When I had the below statement, I was trying to create and initialize values of all variables.

      my (%Aseen, %Bseen, %count, @isec, @diff, @union, @aonly) = ();

      Please let me know what I'm doing wrong.

      Thanks for your help.
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        :)

        perl -MData::Dumper -lwe 'my ( @x, @y, @z ) = ("z", "y", "z"); print D
+umper(\(@x,@y,@z))'
$VAR1 = [
          'z',
          'y',
          'z'
        ];
$VAR2 = [];
$VAR3 = [];

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        my (%Aseen, %Bseen, %count, @isec, @diff, @union, @aonly);

        They all are declared empty. No need to be explicit about it; and as the example above shows, that form of being explicit won't do what you might think anyway.

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        When you have an aggregate (array or hash) in a list that variable will be assigned all the values.    So: 

        my ( @x, @y, @z ) = ("z", "y", "z");

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        Is exactly the same as: 

        my @x = ("z", "y", "z");
my ( @y, @z );

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