Re: Top and bottom 10 percent elements of an array

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Re^2: Top and bottom 10 percent elements of an array by ww (Archbishop) on Apr 29, 2010 at 10:31 UTC
or 100% or 99%...	[reply]
Re^3: Top and bottom 10 percent elements of an array by sesemin (Beadle) on Apr 29, 2010 at 17:25 UTC
Good point. Also, the last two solutions do not work well if the number of array elements are odd. For instance, if we have 11 unique numbers it 5 should be A, 5 B and 1 dash. But both of them print 6 "A"s and 4 "B"s and no dash. I tried to play around with the ranges but could not resolve it. I think 50% is the maximum that we want to go to be able to divide the population of numbers into two categories. Therefore, I am not worry about 75% or higher unless there is another use for this little script.	[reply]
Re^4: Top and bottom 10 percent elements of an array by ikegami (Patriarch) on Apr 29, 2010 at 18:36 UTC
My solution didn't have a problem with 50% of 11 per say. My solution always gave the wrong answer. (The OP confused me by saying 10% should give `B - B - - - - A A -` when that's the output for 20%.) Fixed. `my $portion = 0.50; my @array = (1..11); B B B B B - A A A A A` [download] Same goes for codeacrobat's answer.	[reply] [d/l] [select]