Odd. I would have done

- replace continuous white spaces with a single underscore

$string =~ s/\s+/\_/g;
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The question I have; is it simple preference or is there a technical reason you use the /s approach?

I sense an opportunity for me to learn something, Obi Wan .

perlpal's example was $string =~ s/ {1,}/_/g; which matches a space character while your example $string =~ s/\s+/\_/g; uses the whitespace character class (\s) which matches "\t", "\r", "\n" and "\f" as well as the space character.    In general, the tr/// operator is more efficient then the s/// operator so I try to use it when appropriate.

Thank you!

I was right, this WAS an opportunity for me to learn something.

:: giggle ::

Love days like that.