Re^2: Regex operation optimisation

Odd. I would have done

- replace continuous white spaces with a single underscore

$string =~ s/\s+/\_/g;
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The question I have; is it simple preference or is there a technical reason you use the /s approach?

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Re^3: Regex operation optimisation by jwkrahn (Abbot) on Jul 02, 2010 at 23:36 UTC
perlpal's example was `$string =~ s/ {1,}/_/g;` which matches a space character while your example `$string =~ s/\s+/\_/g;` uses the whitespace character class (`\s`) which matches `"\t"`, `"\r"`, `"\n"` and `"\f"` as well as the space character. In general, the `tr///` operator is more efficient then the `s///` operator so I try to use it when appropriate.	[reply] [d/l] [select]
Re^4: Regex operation optimisation by marinersk (Priest) on Jul 06, 2010 at 21:05 UTC
Thank you! I was right, this WAS an opportunity for me to learn something. :: giggle :: Love days like that.	[reply]