Re: problem in my sub partition

Are you sure the values in your for loop in the sub are what you expect?

...
for($i=1;$i<=$k;$i++){
    print "i = $i, j= $j\n"; # Added to debug
...
[download]

I think you'll find the following does the trick:

for($i=1;$i<$k;$i++){
[download]

(Less than versus less than/equal to)

Comment on Re: problem in my sub partition Select or Download Code

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Re^2: problem in my sub partition by GrandFather (Saint) on Nov 10, 2010 at 00:33 UTC
or if you happen to be writing Perl rather than C you could: `for my $i (1 .. $k - 1) {` [download] True laziness is hard work	[reply] [d/l]