Re^2: list context

It will, because the high-precedence or operator (||) imposes scalar context on its operands and evaluates to a scalar.

Only on the LHS.

use feature qw( say );

my @s = 0 || scalar('a','b','c');
my @l = 0 || ('a','b','c');

say for @s;
say "---";
say for @l;
[download]

c
---
a
b
c
[download]

Comment on Re^2: list context Select or Download Code

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Re^3: list context by chromatic (Archbishop) on Dec 07, 2010 at 00:13 UTC
In this case yes (I was too hasty in my explanation). The operator passes along the context in which it appears to its rhs expression.	[reply]