Re: Regex: not the trailing whitespace

Just delete the trailing whitespace first.

while (<>) {
   s/\s+\z//;
   ...
}
[download]

The second is a look-back assertion so the final trailing whitespace won't just be eaten by the main item

Huh? /[*#]+:?/ cannot eat the trailing whitespace.

So all you need is

/
   ^
   \s*
   ([*#]+:?)
   \s*
   (.*\S)?
   \s*
   $
/sx
[download]

(Is some backtracking protection needed?)

Comment on Re: Regex: not the trailing whitespace Select or Download Code

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Re^2: Regex: not the trailing whitespace by John M. Dlugosz (Monsignor) on Apr 23, 2011 at 06:48 UTC
Huh? `/[#]+:?/` cannot eat the trailing whitespace. No, I mean the `(.)` would. The leading string of bullets is the prefix, and the content of the line after that is the "main item".	[reply] [d/l]
Re^3: Regex: not the trailing whitespace by ikegami (Patriarch) on Apr 23, 2011 at 06:54 UTC
No, I mean the (.) would.* There is no /`(.)`/ in your code. If you mean the /`(.\S)`/, it can't eat the trailing whitespace either.	[reply] [d/l] [select]
Re^4: Regex: not the trailing whitespace by John M. Dlugosz (Monsignor) on Apr 23, 2011 at 07:56 UTC
I was explaining why I added \S to the end. The naive solution, a FAQ here, is (.*)(somethingelse).	[reply]
Re^5: Regex: not the trailing whitespace by ikegami (Patriarch) on Apr 23, 2011 at 08:01 UTC
Re^6: Regex: not the trailing whitespace by John M. Dlugosz (Monsignor) on Apr 23, 2011 at 08:03 UTC
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