Re^4: array in hashes

thank you for your helps.

#!/usr/bin/perl -w
use strict;
my %genome1 = (
   a => [ 10, 15 ],
   b => [  3,  7 ],
   c => [  9, 14 ],
);

my %genome2 = (
   d => [  3, 21 ],
   a => [  3,  4 ],
   g => [  5, 10 ],
   b => [  2,  7 ],
);

for (keys(%genome1)) {
   if ($genome2{$_}) {
      print("$genome1{$_} and $genome2{$_}\n");
   }
}
[download]

we have a in each of hashes (3,4) and (10,15).i want to calculate the slope of the line between (3,4) and (10,15), it means (15-4)/(10-3) or for b we have (2,7) and (3,7),i want (7-7)/(3-2) as output.m=(y2-y1)/(x2-x1).but i dont know how i have to define x and y for numbers in hashes.

Comment on Re^4: array in hashes Download Code

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Re^5: array in hashes by moritz (Cardinal) on Jul 29, 2011 at 09:54 UTC
So, did you read perlreftut? We're not here to write the code for you, but to help you to learn enough Perl and programminig so that you can do it yourself. Perl 6 - second systems done right	[reply]
Re^5: array in hashes by fisher (Priest) on Jul 29, 2011 at 10:07 UTC
i want (7-7)/(3-2) as output. Is this what you want? `for (keys(%genome1)) { if ($genome2{$_}) { print "for ".$_." it is (".${$genome1{$_}}[1]."-". ${$genome2{$_}}[1].")/(".${$genome1{$_}}[0]."-".${$genome2{$_}}[ +0].")\n"; } }` [download]	[reply] [d/l]
Re^6: array in hashes by JavaFan (Canon) on Jul 29, 2011 at 10:19 UTC
There's no need for the additional blocks. Writing `$genome1{$_}[1]` instead of `${$genome1{$_}}[1]` is just fine.	[reply] [d/l] [select]
Re^7: array in hashes by AnomalousMonk (Archbishop) on Jul 29, 2011 at 15:37 UTC
Further to JavaFan's point about clarity, there's also no need to go overboard using concatenation for complex hash or array values in a string. They will interpolate just fine: `>perl -wMstrict -le "my %hash = ( a => [11,22], b => [33,44], ); my $hashref = { c => [55,66], d => [77,88], }; ;; print qq{$hash{a}[0] $hash{b}[1] $hashref->{d}[1]}; " 11 44 88` [download]	[reply] [d/l]
Re^7: array in hashes by fisher (Priest) on Jul 29, 2011 at 14:02 UTC
Yes, I know. I wrote this for clarity.	[reply]
Re^8: array in hashes by JavaFan (Canon) on Jul 29, 2011 at 14:55 UTC
Re^6: array in hashes by persianswallow (Novice) on Jul 29, 2011 at 10:44 UTC
thank you soooooooooooooo much.:-) i need amount of those calculation.i mean (15-4)/(10-3)is equal to 1.5714286 but it doesnt print that.	[reply]