Re^5: array in hashes

i want (7-7)/(3-2) as output.

Is this what you want?

for (keys(%genome1)) {
   if ($genome2{$_}) {
      print "for ".$_." it is (".${$genome1{$_}}[1]."-".
      ${$genome2{$_}}[1].")/(".${$genome1{$_}}[0]."-".${$genome2{$_}}[
+0].")\n";
   }
}
[download]

Comment on Re^5: array in hashes Download Code

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Re^6: array in hashes by JavaFan (Canon) on Jul 29, 2011 at 10:19 UTC
There's no need for the additional blocks. Writing `$genome1{$_}[1]` instead of `${$genome1{$_}}[1]` is just fine.	[reply] [d/l] [select]
Re^7: array in hashes by AnomalousMonk (Archbishop) on Jul 29, 2011 at 15:37 UTC
Further to JavaFan's point about clarity, there's also no need to go overboard using concatenation for complex hash or array values in a string. They will interpolate just fine: `>perl -wMstrict -le "my %hash = ( a => [11,22], b => [33,44], ); my $hashref = { c => [55,66], d => [77,88], }; ;; print qq{$hash{a}[0] $hash{b}[1] $hashref->{d}[1]}; " 11 44 88` [download]	[reply] [d/l]
Re^7: array in hashes by fisher (Priest) on Jul 29, 2011 at 14:02 UTC
Yes, I know. I wrote this for clarity.	[reply]
Re^8: array in hashes by JavaFan (Canon) on Jul 29, 2011 at 14:55 UTC
Clarity? 3 extra, not-needed, punctuation characters that hardly anyone ever use? I fail to see why that brings clarity, or who benefits from it.	[reply]
Re^6: array in hashes by persianswallow (Novice) on Jul 29, 2011 at 10:44 UTC
thank you soooooooooooooo much.:-) i need amount of those calculation.i mean (15-4)/(10-3)is equal to 1.5714286 but it doesnt print that.	[reply]