Re: join two hashes

"Best way"? By which measurement? I may write it as (untested code):

my %new_hash;
$new_hash{$_} = [$rep{$_}, $comb{$_}] for keys %rep;
[download]

my %new_hash = map {($_, [$rep{$_}, $comb{$_}])} keys %rep;
[download]

Comment on Re: join two hashes Select or Download Code

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Re^2: join two hashes by Anonymous Monk on Jul 30, 2011 at 10:33 UTC
in this case i have this error `key=ARRAY<0x1889c64>`	[reply] [d/l]
Re^3: join two hashes by choroba (Cardinal) on Jul 30, 2011 at 10:49 UTC
It is not an error. The value of the key is the array reference as you wanted (or at least we can guess so, because a comma is missing in your spec). See perlref.	[reply]
Re^3: join two hashes by JavaFan (Canon) on Jul 30, 2011 at 11:00 UTC
You mean, if you run my code, the error you get is `key=ARRAY<0x1889c64>`? That would be quite strange, as that's not a standard Perl error. And the code snippet I gave doesn't do any I/O by itself.	[reply] [d/l]
Re^4: join two hashes by Anonymous Monk on Jul 30, 2011 at 11:09 UTC
your code in my script is as follow: `my %new_hash = map {($_, [$rep{$_}, $comb{$_}])} keys %rep; for my $key(keys %new_hash){ print "$key=$new_hash{$key}\n";}` [download] and for each key has an error like that i mentioned.	[reply] [d/l]
Re^5: join two hashes by johngg (Canon) on Jul 30, 2011 at 11:54 UTC
Re^5: join two hashes by JavaFan (Canon) on Jul 30, 2011 at 15:54 UTC
Re^3: join two hashes by Anonymous Monk on Jul 30, 2011 at 10:37 UTC
What does that mean? Its like saying the answer to Life, the Universe, and Everything, is 42 -- does not compute	[reply]