Re^2: join two hashes

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Re^3: join two hashes by choroba (Cardinal) on Jul 30, 2011 at 10:49 UTC
It is not an error. The value of the key is the array reference as you wanted (or at least we can guess so, because a comma is missing in your spec). See perlref.	[reply]
Re^3: join two hashes by JavaFan (Canon) on Jul 30, 2011 at 11:00 UTC
You mean, if you run my code, the error you get is `key=ARRAY<0x1889c64>`? That would be quite strange, as that's not a standard Perl error. And the code snippet I gave doesn't do any I/O by itself.	[reply] [d/l]
Re^4: join two hashes by Anonymous Monk on Jul 30, 2011 at 11:09 UTC
your code in my script is as follow: `my %new_hash = map {($_, [$rep{$_}, $comb{$_}])} keys %rep; for my $key(keys %new_hash){ print "$key=$new_hash{$key}\n";}` [download] and for each key has an error like that i mentioned.	[reply] [d/l]
Re^5: join two hashes by johngg (Canon) on Jul 30, 2011 at 11:54 UTC
That's not an an error, that's what each value of the hash holds; a scalar reference to an anonymous array. Consider:- `knoppix@Microknoppix:~$ perl -E ' > %rep = ( one => 123, two => 456 ); > %comb = ( one => 987, two => 654 ); > %new = map { $_, [ $rep{ $_ }, $comb{ $_ } ] } keys %rep; > say qq{$_ => $new{ $_ } => @{ $new{ $_ } }} for keys %new;' one => ARRAY(0x81a1530) => 123 987 two => ARRAY(0x8195d00) => 456 654 knoppix@Microknoppix:~$` [download] You have to de-reference the array reference (`@{ $new{ $_ } }` see perlreftut) to get at the contents. Update: Added documentation reference. Cheers, JohnGG	[reply] [d/l] [select]
Re^5: join two hashes by JavaFan (Canon) on Jul 30, 2011 at 15:54 UTC
The only error is on your side. You have a hash, whose values are arrayreferences, as specified. You are printing those references - which means they are stringified. What you are seeing is the stringification of the arrayref. There is no bug.	[reply]
Re^3: join two hashes by Anonymous Monk on Jul 30, 2011 at 10:37 UTC
What does that mean? Its like saying the answer to Life, the Universe, and Everything, is 42 -- does not compute	[reply]