in reply to How do I read this line of code?
for my $string ("\n", ' ' x ( $level - 1 ), shift @pre_push) { $buff = $buff . $string; }
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Re^2: How do I read this line of code?
by Tux (Canon) on Sep 29, 2011 at 09:33 UTC | |
by pmarcoen (Novice) on Sep 29, 2011 at 09:42 UTC | |
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Re^2: How do I read this line of code?
by Anonymous Monk on Sep 29, 2011 at 09:32 UTC | |
by GrandFather (Saint) on Sep 29, 2011 at 09:46 UTC | |
by choroba (Cardinal) on Sep 29, 2011 at 09:46 UTC |