Re^2: How do I read this line of code?

TIMTOWTDI. I would never use a for loop for this, but it might well be a simplification of what in earlier versions warranted the for loop.

$buff .= $_ for  "\n", '  ' x ( $level - 1 ), shift @pre_push;

=>

{   my $indent = " " x ($level - 1);
    $buf .= "\n" . $indent . shift @pre_push;
    }

or

$buff .= "\n" . (" " x ($level - 1)) . shift @pre_push;

or

$buff .= join "" => "\n", " " x ($level - 1), shift @pre_push;

or

$buff .= join ((" " x ($level - 1)) => "\n", shift @pre_push);

or

...
[download]

Enjoy, Have FUN! H.Merijn

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Re^3: How do I read this line of code? by pmarcoen (Novice) on Sep 29, 2011 at 09:42 UTC
Okay, this clarifies a lot, so there is no real need for a for loop. The for loop is not used to loop through the elements of the array, but rather to loop through the things we want to add to $buff being: a newline spaces the entire content of the array	[reply]