in reply to access to sub of package

The "usage" function is in the "A" namespace, therefore... A::usage(...)
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Re^2: access to sub of package
by jeanluca (Deacon) on Feb 28, 2006 at 14:55 UTC
    Well, that didn't work. Here is some code that demonstrates how I did it:
    package B:
    package B ;
sub usage {
    print "test\n" ;
}

    [download]

    main script
    use B ;
B::usage() ;

    [download]
    If I run this script I get:
    Undefined subroutine &B::usage called at ./r.pl line 5. Any suggestions ?

    Luca
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      The B module is part of the standard distribution and doesn't have a usage sub, so yeah you'll get an error. Use a better example module name (e.g. Foo or the like) and you'll get better results.

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        just one other thing. The difference with the example, and the situation I've here is that I've the package name inside a variable, like: $var = "B" ;Now this doesn't work:
        $var::usage() ;
        But this does
        $var->usage
        Do you know why this is ?

        Thanks
        Luca
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        Yep, thnks, I noticed that when I add use lib '.'; it works too!!

        Luca
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