Re^2: access to sub of package

Well, that didn't work. Here is some code that demonstrates how I did it:
package B:

package B ;
sub usage {
    print "test\n" ;
}
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main script

use B ;
B::usage() ;
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If I run this script I get:
Undefined subroutine &B::usage called at ./r.pl line 5. Any suggestions ?

Luca

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Re^3: access to sub of package by Fletch (Bishop) on Feb 28, 2006 at 14:57 UTC
The B module is part of the standard distribution and doesn't have a `usage` sub, so yeah you'll get an error. Use a better example module name (e.g. `Foo` or the like) and you'll get better results.	[reply] [d/l] [select]
Re^4: access to sub of package by jeanluca (Deacon) on Feb 28, 2006 at 15:09 UTC
just one other thing. The difference with the example, and the situation I've here is that I've the package name inside a variable, like: $var = "B" ;Now this doesn't work: `$var::usage() ;` But this does `$var->usage` Do you know why this is ? Thanks Luca	[reply] [d/l] [select]
Re^5: access to sub of package by Fletch (Bishop) on Feb 28, 2006 at 15:16 UTC
Because the later is a method lookup (which allows a scalar containing a package name to be used) while the former is a syntax error (you've named a scalar `$usage` in the package `var`, then you're trying to call it as a function). If you need to call something in a dynamically determined package you'll need to use `eval` or something like `{ no strict 'refs'; &{"${var}::usage"}( ) }`).	[reply] [d/l] [select]
Re^4: access to sub of package by jeanluca (Deacon) on Feb 28, 2006 at 15:04 UTC
Yep, thnks, I noticed that when I add use lib '.'; it works too!! Luca	[reply]