Re^2: Creating 'new' subroutine.

if the second element is empty
then shift @_ moves to the $_ nothing
which means scalar @_ returns zero
in which case : {} adds into hash nothing,
but creates reference to it
so $options {@_} would do the trick, I guess

please correct if it's wrong

updated

thanks for the correction snippet was incorrect

Comment on Re^2: Creating 'new' subroutine.

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Re^3: Creating 'new' subroutine. by Anonymous Monk on Oct 11, 2013 at 11:00 UTC
@_ is an array, an array in scalar context returns the number of elements (a number), and anumber is never a reference	[reply]
Re^4: Creating 'new' subroutine. by Lennotoecom (Pilgrim) on Oct 11, 2013 at 11:15 UTC
yes but @a = (); $b = {@a}; will create a reference to a hash	[reply]
Re^5: Creating 'new' subroutine. by Anonymous Monk on Oct 11, 2013 at 11:17 UTC
yes but and this is relevant to the logic error in Re^2: Creating 'new' subroutine. how?	[reply]
Re^6: Creating 'new' subroutine. by Lennotoecom (Pilgrim) on Oct 11, 2013 at 11:20 UTC
Re^7: Creating 'new' subroutine. by Anonymous Monk on Oct 11, 2013 at 11:27 UTC
Some notes below your chosen depth have not been shown here
Re^3: Creating 'new' subroutine. by nitin.sh1982 (Initiate) on Oct 17, 2013 at 04:27 UTC
Thanks for the reply. I still am far from testing it as we are running on mac, and are struggling with the setup. So, do you mean scalar @_ determines how many elements to be added into hash while creating the reference?	[reply]