You don't need the my $lefthand= (); line since you never use a scalar named "lefthand". $lefthand{dsfddf} accesses the hash. You use "$" because you are getting a scalar back, but it has nothing to do with the variable $lefthand.

        - tye (but my friends call me "Tye")

In reply to RE: RE: Re: dsfddf by tye
in thread Reaped: dsfddf by NodeReaper

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