Re: hash problem

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Re^2: hash problem by CountZero (Bishop) on Jul 09, 2004 at 18:33 UTC
Are you sure it works? When I inspect your `@hash` with `print Dumper(\@hash);` all I get is `$VAR1 = [];` CountZero "If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law	[reply] [d/l] [select]
Re^3: hash problem by sacked (Hermit) on Jul 09, 2004 at 18:37 UTC
You want `print Dumper \%hash`, not `\@hash`. `@hash{@keys}` is a hash slice, not an array. --sacked	[reply] [d/l] [select]
Re^4: hash problem by CountZero (Bishop) on Jul 09, 2004 at 18:41 UTC
In that case you get as result `$VAR1 = { 'three' => undef, 'one' => undef, 'two' => undef };` [download] which isn't at all what the OP asked for. CountZero "If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law	[reply] [d/l]
Re^3: hash problem by sweetblood (Prior) on Jul 09, 2004 at 18:48 UTC
perhaps I'm mistaken but I don't think so, try: `print Dumper %hash` [download] If I'm wrong then I've mis-understood something Sweetblood	[reply] [d/l]
Re^4: hash problem by CountZero (Bishop) on Jul 09, 2004 at 18:51 UTC
IF you try that, Data::Dumper gives you: `$VAR1 = 'three'; $VAR2 = undef; $VAR3 = 'one'; $VAR4 = undef; $VAR5 = 'two'; $VAR6 = undef;` [download] CountZero "If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law	[reply] [d/l]