in reply to Re: hash problem
in thread hash problem

Are you sure it works? When I inspect your @hash with print Dumper(\@hash); all I get is $VAR1 = [];

CountZero

"If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law

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Re^3: hash problem
by sacked (Hermit) on Jul 09, 2004 at 18:37 UTC
    You want print Dumper \%hash, not \@hash.

    @hash{@keys} is a hash slice, not an array.

    --sacked
[reply]
[d/l]
[select]
      In that case you get as result 
      $VAR1 = {
          'three' => undef,
          'one' => undef,
          'two' => undef
        };

      [download]
      which isn't at all what the OP asked for.

      CountZero

      "If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law

[reply]
[d/l]
Re^3: hash problem
by sweetblood (Prior) on Jul 09, 2004 at 18:48 UTC
    perhaps I'm mistaken but I don't think so, try:
    print Dumper %hash

    [download]
    If I'm wrong then I've mis-understood something

    Sweetblood

[reply]
[d/l]
      IF you try that, Data::Dumper gives you: 
      $VAR1 = 'three';
$VAR2 = undef;
$VAR3 = 'one';
$VAR4 = undef;
$VAR5 = 'two';
$VAR6 = undef;

      [download]

      CountZero

      "If you have four groups working on a compiler, you'll get a 4-pass compiler." - Conway's Law

[reply]
[d/l]

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