in reply to passing array ref without variable

Yes, just try it – and see what happens with Data::Dumper or any of its ilk. (Also nice to use strictures and warnings!) 

>perl -wMstrict -le
"use Data::Dumper;
 my %hash = qw(a 1  b 2  c 3  d 4);
 my_function([keys %hash]);
 sub my_function {
   my $arr_ref = shift;
   print Dumper $arr_ref;
   }
"
$VAR1 = [
          'c',
          'a',
          'b',
          'd'
        ];

[download]

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Re^2: passing array ref without variable
by vit (Friar) on May 03, 2010 at 15:23 UTC
    Can I pass somehow an array ref of values without separately forming an array? Maybe using foreach...
[reply]
      Why would you want to? Inline anonymous array construction is a trivial number of characters and is robust. This sounds like an XY Problem.
[reply]
      I suppose what you really want/need is to pass the hash as reference, like this you don't need to pass the values and the keys separately.

       call(\%hash)

      If you explicitly want to pass the reference of a copy do this

       call( { %hash } )

      the { ... } returns a ref of an anonymous hash of the list expanded from %hash, i.e. the ref of a hashcopy!

      Cheers Rolf

[reply]
[d/l]
[select]
        No I do not want to pass a hash. What I want to do is having a hash ($h{key} = value) and 
        sub my_function 
{
my $arr_ref = shift;
...
}

        [download]
        I can pass keys as an array ref by 
        my_function([keys %hash])

        [download]
        Now, I want to pass values as an array ref in a shortest way without forming an array. Is it possible?
[reply]
[d/l]
[select]

      Why would you want to? And how could you? It sounds like you (vit) are asking "Can I take a reference to an array that does not exist?".

[reply]

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