Re^2: passing array ref without variable

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Re^3: passing array ref without variable by kennethk (Abbot) on May 03, 2010 at 16:05 UTC
Why would you want to? Inline anonymous array construction is a trivial number of characters and is robust. This sounds like an XY Problem.	[reply]
Re^3: passing array ref without variable by LanX (Saint) on May 03, 2010 at 17:03 UTC
I suppose what you really want/need is to pass the hash as reference, like this you don't need to pass the values and the keys separately. `call(\%hash)` If you explicitly want to pass the reference of a copy do this `call( { %hash } )` the `{ ... }` returns a ref of an anonymous hash of the list expanded from %hash, i.e. the ref of a hashcopy! Cheers Rolf	[reply] [d/l] [select]
Re^4: passing array ref without variable by vit (Friar) on May 03, 2010 at 21:07 UTC
No I do not want to pass a hash. What I want to do is having a hash ($h{key} = value) and `sub my_function { my $arr_ref = shift; ... }` [download] I can pass keys as an array ref by `my_function([keys %hash])` [download] Now, I want to pass values as an array ref in a shortest way without forming an array. Is it possible?	[reply] [d/l] [select]
Re^5: passing array ref without variable by FunkyMonk (Bishop) on May 03, 2010 at 21:15 UTC
Hmmm. You know that you get the keys of a hash using a function called keys. What do you think would be the name of the function that returns the values of a hash?	[reply]
Re^5: passing array ref without variable by LanX (Saint) on May 03, 2010 at 21:26 UTC
Is it possible? Short answer, yes! `my_function([values %hash])` but please be aware that this is only a flat copy. Cheers Rolf	[reply] [d/l]
Re^6: passing array ref without variable by Anonymous Monk on May 04, 2010 at 00:50 UTC
Re^7: passing array ref without variable by LanX (Saint) on May 04, 2010 at 06:26 UTC
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Re^3: passing array ref without variable by AnomalousMonk (Archbishop) on May 03, 2010 at 16:15 UTC
Why would you want to? And how could you? It sounds like you (vit) are asking "Can I take a reference to an array that does not exist?".	[reply]