First of all, i'd write:print $var ? 'yes' : 'no'
wouldnt this print yes or no depending on $var...it looks like the
Anonymous Monk wants to print yes or no depending on whether $var has a value or not
$var ? print 'yes' : print 'no'
seems right to me, am i missing something?
Update: I just started learning how ?: works, so i just wanted to know why
print $var ? 'yes' : 'no'
will also work, i guess im not understanding how it evaluates $var...the way im reading ?: is
if 1st arg (print $var) then second (yes) else third(no) so how does it know that you actually want to print yes or no? with the way im looking at it, it is
if(print $var){
'yes'
}else{
'no'
}
anyone care to explain to me, id appreciate it greatly