The simple answer is that you cannot store a coderef with arguments. What would that mean if you could?
sub test{ print @_; }
## THIS DOESN'T WORK, BUT IF IT DID...
my $coderef = \&test( 'this is the argument' );
$coderef->(); # would print 'this is the argument' );
$coderef->( 'a different argument' );
# Would print 'this is the argument'!!
If you really want the sub to always have the same argument(s), then they aren't argument(s)--they are constant(s) :) -- so code the sub that way.
sub test{ print 'this is the argument'; }
my $coderef = \&test;
$coderef->(); # prints 'this is the argument' );
$coderef->( 'a different argument' );
# Prints 'this is the argument'!!
Problem solved:)
However, if you want to pass different arguments when you invoke the coderef, do so.
my $coderef = sub{ print @_; };
$coderef->( 'Some', 'args' );
# Prints 'someargs'
Examine what is said, not who speaks.
"Efficiency is intelligent laziness." -David Dunham
"When I'm working on a problem, I never think about beauty. I think only how to solve the problem. But when I have finished, if the solution is not beautiful, I know it is wrong." -Richard Buckminster Fuller
If I understand your problem, I can solve it! Of course, the same can be said for you.
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