Why the followig code is not working.
My son, let me give you some priestly advice:
When you want to find out why something isn't working you
first have to establish for the reader what your criteria
for "working" is. In other words: what were
you expecting to happen, and what really happened.
As has been noted before and I quote from the perldoc
In list context, returns a list value consisting of the
ments of LIST in the opposite order. In scalar context
catenates the elements of LIST and returns a string val
all characters in the opposite order.
print reverse <>; # line tac, last line f
undef $/; # for efficiency of <>
print scalar reverse <>; # character tac, last l
So with that in mind, if I run the following on-liner:
perl -e 'print scalar reverse "dog" . "\n";'
I get the following terse output:
Let us play... If I run the following one liner:
perl -e 'print join( ",", reverse ( split "", "dog")) . "\n";'
I am now feeding reverse an array and I can now get the
I hope this clears things up for you....
Peter L. Berghold -- Unix Professional
Peter -at- Berghold -dot- Net; AOL IM redcowdawg Yahoo IM: blue_cowdawg
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