As
diotalevi discovered, the OP was directly
plagiarized from
this site, which has a date of July 6, 2005:
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The following subroutine returns its argument with any leading newline
+s
removed:
sub xxx {
my $s = shift;
$s =~ s/^\n+//;
$s;
}
However, if this function is called from the replacement part of
a s///em, the /m semantics is carried over, and internal newlines
will be deleted.
I've confirmed the bug to be present in 5.000, 5.004_0[45], 5.005_0x,
5.6.x and 5.8.x, including 5.8.7. However, the bug isn't present in
any of the 5.9.x versions of perl.
Full test:
#!/usr/bin/perl
use strict;
use warnings;
no warnings qw /syntax/;
use Test::More tests => 1;
#
# Delete any leading newlines.
#
sub xxx {
my $s = shift;
$s =~ s/^\n+//;
$s;
}
my $a = "A\n\nB"; $a =~ s/([\s\w]+)/xxx $1/e;
my $b = "A\n\nB"; $b =~ s/([\s\w]+)/xxx $1/em;
is ($b, $a);
__END__
1..1
not ok 1
# Failed test (eep at line 21)
# got: 'A
# B'
# expected: 'A
#
# B'
# Looks like you failed 1 test of 1.
Update::
(his previous SoPW is 'my' with 'if 0' retains old value, which probably wasn't on p5p as it has been beaten to death already),
Guess again ... Re: 'my' with 'if 0' retains old value, points to the p5p site from which jesuashok plagiarized it.
s''(q.S:$/9=(T1';s;(..)(..);$..=substr+crypt($1,$2),2,3;eg;print$..$/
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