for (scalar($i=3, $i=2, $i=1)) {
  print "$_ and $i\n";
}
[download]

$i=3, $i=2, $i=1;
for ($i, $i, $i) {
  print "$_ and $i\n";
}
[download]

The interesting part

for (0+($i=3), 0+($i=2), $i=1) {
  print "$_ and $i\n";
}
[download]

I can get the effect I expected by doing this:

for (0+($i=3), 0+($i=2), $i=1) {
  print "$_ and $i\n";
}
[download]

In your example you create

for ( temp, temp2, $i ) {
[download]

Boris

Maybe a better way to think about it is that you created an array of three elements, each element is pointing to the $i variable. However, because you are initializing $i for each element in the list, the elements in the list all contain the same value (in this case, the final value of $i: 1), since they're pointing to the current value of $i.

Scalar assignments yield the lvalue on the left, not the value on the right. Now can you make that fit with your "interesting part" and understand why it works as it does?

I didn't have any difficulty understanding why the interesting part worked.

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