Monads in Perl

In the past, we've had meditaton on coroutines, continuations, haskell, and other functional topics. So I thought I'd throw my recently completed "Monads in Perl" tutorial out there for discussion. There is no real reason to use monads in perl, but hey, TMTOWTDI.

-- All code is 100% tested and functional unless otherwise noted.

Comment on Monads in Perl

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Re: Monads in Perl by jryan (Vicar) on Aug 31, 2004 at 17:50 UTC
As you said, "hey, TMTOWTDI." (: `print parse_equation("Div Div Con 18 Con 2 Con 3"); # just a sexeger sub parse_equation { my $r = reverse $_[0]; $r =~ s!(\d+(?:\.\d+)?) noC (\d+(?:\.\d+)?) noC viD! reverse($2)/reverse($1) . ' noC' !e while $r =~ /viD/; return scalar reverse $r; }` [download]	[reply] [d/l]
Re: Monads in Perl by adrianh (Chancellor) on Sep 01, 2004 at 13:19 UTC
This is nitpicking an otherwise nice little article (sorry :-) but: closures (also know as anonymous subroutines) I really wish that people wouldn't use closures and anonymous subroutines as synonyms. Not all closures are anonymous. Not all anonymous subroutines are closures. I know people do - but we shouldn't encourage them! It only leads to confusion.	[reply]
Re: Monads in Perl by FoxtrotUniform (Prior) on Aug 31, 2004 at 22:02 UTC
Nice tutorial! Anyone else interested in joining the PerlMonks Haskell Fanboys Club? :-) `-- F o x t r o t U n i f o r m Found a typo in this node? /msg me % man 3 strfry`	[reply]


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