Re^2: counting inside the loop


The stupid question is the question not asked
	PerlMonks

by sarvan (Sexton)

on Jul 01, 2011 at 11:09 UTC ( [id://912334]=note: print w/replies, xml )

Need Help??

Hi, For this,

$count=($str=~ tr/($t1)//);
[download]

if $t1 has ab. i just want to count how many times ab is their in $str. together. not as seperately 'a' 'b'.

What can be done for that..

Comment on Re^2: counting inside the loop Download Code

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Re^3: counting inside the loop by Anonymous Monk on Jul 01, 2011 at 11:27 UTC
AnomalousMonk explains in Re^2: counting inside the loop, use `my $count = () = m/ab/g;`	[reply] [d/l]
Re^4: counting inside the loop by sarvan (Sexton) on Jul 04, 2011 at 05:19 UTC
Hi, `$s='finding related pages finding on the world wide web'; my $count=$s=~ m/finding/g; print $count;` [download] I expect the result as 2.. becus "finding" exists two times in $s. but the output is 1. Why?? thanks	[reply] [d/l]
Re^5: counting inside the loop by Anonymous Monk on Jul 04, 2011 at 06:22 UTC
It is because you don't know how to copy/paste The extra `( ) =` are required --- probably the worst syntax in all of perl, but its what you need if you have built-in regexes without objects, and you don't store matches in an array.	[reply] [d/l]

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