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I have a possibly bad habit to compact boring parts of my code like this:

if( exists($hash->{akey}) && defined($m=$hash->{akey}) && ($m==1) ){ $ +y = $m; ... } # don't trust $m here

But in this case it has unexpected results. This is the 1st part where a hash is constructed based on whether a key in another hash exists:

use strict; use warnings; use Data::Dumper; my %tests = ( 'a' => 10, 'b' => 20, ); my $m; # this seems to assign $m once and never bother to check again my %hash = ( 'b' => exists($tests{'b'}) && defined($m=$tests{'b'}) ? $m : 0, 'a' => exists($tests{'b'}) && defined($m=$tests{'a'}) ? $m : 0, ); print Dumper(\%hash); # this works as expected $m = 10; my %hash2 = ( '1' => $m++, '2' => $m++, '3' => $m++ ); print Dumper(\%hash2);
$VAR1 = { 'a' => 10, 'b' => 10 }; $VAR1 = { '1' => 10, '2' => 11, '3' => 12 };

Does anyone have an explanation? And is my habit bad?


In reply to Ternary Quizical behaviour? by bliako

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