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Using perl module if env is enabled (FA:6/7/6)+/- 2019-12-09 15:13 6 years ago
[ovedpo15]
Re: Using perl module if env is enabled 2019-12-09 15:19 6 years ago
[Corion]
Re: Using perl module if env is enabled 2019-12-09 15:20 6 years ago
[tobyink]
Re: Using perl module if env is enabled (1)+/- 2019-12-09 15:24 6 years ago
[haukex]
Re^2: Using perl module if env is enabled 2019-12-09 16:07 6 years ago
[tobyink]
Re: Using perl module if env is enabled 2019-12-09 16:42 6 years ago
[davido]
Re: Using perl module if env is enabled (-MXYZ PERL5OPT=-MXYZ perlcritic -brutal) [10] 2019-12-10 04:25 6 years ago
Re: Using perl module if env is enabled [9] 2019-12-10 16:40 6 years ago
Perl script compressor (A:4/22/4)+/- 2019-12-08 04:54 6 years ago
Re: Perl script compressor 2019-12-08 07:09 6 years ago
[marto]
Re: Perl script compressor 2019-12-08 08:14 6 years ago
[haukex]
Re: Perl script compressor (1/9/3)+/- 2019-12-08 14:22 6 years ago
Re^2: Perl script compressor (1/8/3)+/- 2019-12-08 19:17 6 years ago
Re^3: Perl script compressor (2/7/3)+/- 2019-12-08 20:18 6 years ago
Re^4: Perl script compressor 2019-12-08 20:49 6 years ago
[afoken]
Re^4: Perl script compressor (1/5/2)+/- 2019-12-09 07:26 6 years ago
Re^5: Perl script compressor (1/4/1)+/- 2019-12-09 22:05 6 years ago
[afoken]
Re^6: Perl script compressor (2/3)+/- 2019-12-10 03:22 6 years ago
Re^7: Perl script compressor (1)+/- 2019-12-10 05:06 6 years ago
Re^8: Perl script compressor 2019-12-10 05:30 6 years ago
[soonix]
Re^7: Perl script compressor 2019-12-10 06:41 6 years ago
[marto]
Re: Perl script compressor (2/9/1)+/- 2019-12-08 17:33 6 years ago
[afoken]
Re^2: Perl script compressor (1/4/1)+/- 2019-12-08 18:08 6 years ago
[shmem]
Re^3: Perl script compressor (1/3/1)+/- 2019-12-08 22:25 6 years ago
[haukex]
Re^4: Perl script compressor (2/1)+/- 2019-12-08 23:12 6 years ago
[stevieb]
Re^5: Perl script compressor 2019-12-09 03:26 6 years ago
[marto]
Re^5: Perl script compressor 2019-12-09 11:18 6 years ago
Re^2: Perl script compressor [3](3)+/- 2019-12-08 18:35 6 years ago
Re^3: Perl script compressor 2019-12-08 18:46 6 years ago
[stevieb]
Re^3: Perl script compressor 2019-12-08 19:32 6 years ago
[marto]
Re^3: Perl script compressor 2019-12-08 21:40 6 years ago
[davido]
Best practices for local libraries (F:6/9/1)+/- 2019-12-07 04:11 6 years ago
[Barrabas]
Re: Best practices for local libraries 2019-12-07 09:49 6 years ago
[haukex]
Re: Best practices for local libraries (1/2)+/- 2019-12-07 10:19 6 years ago
[misc]
Re^2: Best practices for local libraries (1)+/- 2019-12-07 10:28 6 years ago
[haukex]
Re^3: Best practices for local libraries 2019-12-07 11:04 6 years ago
[misc]
Re: Best practices for local libraries 2019-12-07 19:55 6 years ago
Re: Best practices for local libraries (1)+/- 2019-12-08 02:13 6 years ago
[NERDVANA]
Re^2: Best practices for local libraries 2019-12-08 09:27 6 years ago
[dsheroh]
Re: Best practices for local libraries 2019-12-08 10:46 6 years ago
Re: Best practices for local libraries [3] 2019-12-10 03:54 6 years ago
using perl to find words for scrabble (FA:8/17/2)+/- 2019-09-04 23:06 6 years ago
Re: using perl to find words for scrabble (1/4)+/- 2019-09-04 23:54 6 years ago
[pryrt]
Re^2: using perl to find words for scrabble (1/3)+/- 2019-09-07 17:46 6 years ago
Re^3: using perl to find words for scrabble (1/2)+/- 2019-09-07 18:08 6 years ago
[pryrt]
Re^4: using perl to find words for scrabble (1)+/- 2019-09-12 02:54 6 years ago
Re^5: using perl to find words for scrabble 2019-09-12 13:07 6 years ago
[pryrt]
Re: using perl to find words for scrabble 2019-09-04 23:54 6 years ago
[jcb]
Re: using perl to find words for scrabble (1/3)+/- 2019-09-05 00:13 6 years ago
[tybalt89]
Re^2: using perl to find words for scrabble (1/2)+/- 2019-09-16 22:31 6 years ago
Re^3: using perl to find words for scrabble (1)+/- 2019-09-16 23:11 6 years ago
[tybalt89]
Re^4: using perl to find words for scrabble 2019-09-17 00:59 6 years ago
[tybalt89]
Re: using perl to find words for scrabble -- further suggestions 2019-09-05 08:39 6 years ago
Re: using perl to find words for scrabble 2019-09-06 04:01 6 years ago
[atcroft]
Re: using perl to find words for scrabble 2019-09-12 10:52 6 years ago
[QM]
Re: using perl to find words for scrabble (1)+/- 2019-10-31 01:42 6 years ago
[1nickt]
Re^2: using perl to find words for scrabble 2019-11-01 07:09 6 years ago
Re: using perl to find words for scrabble (1)+/- 2019-12-09 10:56 6 years ago
[hippo]
Re^2: using perl to find words for scrabble 2019-12-09 21:02 6 years ago
[tybalt89]
curious behavior: why does it do this? (A:4/15/1)+/- 2018-11-27 23:09 7 years ago
Re: curious behavior: why does it do this? (1)+/- 2018-11-27 23:33 7 years ago
[haukex]
Re^2: curious behavior: why does it do this? 2018-11-28 01:26 7 years ago
Re: curious behavior: why does it do this? (2/9)+/- 2018-11-27 23:43 7 years ago
[davido]
Re^2: curious behavior: why does it do this? (3/7)+/- 2018-11-28 00:45 7 years ago
[syphilis]
Re^3: curious behavior: why does it do this? 2018-11-28 01:24 7 years ago
Re^3: curious behavior: why does it do this? 2018-11-28 05:21 7 years ago
Re^3: curious behavior: why does it do this? (2/4)+/- 2018-11-28 15:12 7 years ago
[haukex]
Re^4: curious behavior: why does it do this? (1/2)+/- 2018-11-28 18:18 7 years ago
Re^5: curious behavior: why does it do this? (1)+/- 2018-11-29 03:47 7 years ago
[syphilis]
Re^6: curious behavior: why does it do this? 2018-11-30 14:09 7 years ago
[haukex]
Re^4: curious behavior: why does it do this? 2018-11-29 00:10 7 years ago
[rsFalse]
Re^2: curious behavior: why does it do this? 2018-11-28 06:55 7 years ago
Re: curious behavior: why does it do this? (updated!) 2018-11-30 14:20 7 years ago
[haukex]
Re: curious behavior: why does it do this? (1)+/- 2019-12-10 01:33 6 years ago
Re^2: curious behavior: why does it do this? 2019-12-10 05:21 6 years ago
[haukex]
What operator prepends? (A:6/10/1)+/- 2006-01-25 14:05 20 years ago
[EdwardG]
Re: What operator prepends? 2006-01-25 14:16 20 years ago
[pKai]
Re: What operator prepends? 2006-01-25 14:17 20 years ago
Re: What operator prepends? 2006-01-25 14:35 20 years ago
[Fletch]
Re: What operator prepends? 2006-01-25 16:43 20 years ago
[kwaping]
Re: What operator prepends? (1)+/- 2006-01-25 17:54 20 years ago
[ptum]
Re^2: What operator prepends? 2019-12-09 13:10 6 years ago
Re: What operator prepends? (1/3)+/- 2006-01-25 17:57 20 years ago
Re^2: What operator prepends? (1/2)+/- 2006-01-25 21:56 20 years ago
Re^3: What operator prepends? (1)+/- 2006-01-25 22:21 20 years ago
Re^4: What operator prepends? 2006-01-26 03:46 20 years ago
RFC: "assignary" operator ?= : (FA:7/46/9)+/- 2019-12-07 16:01 6 years ago
Re: RFC: "assignary" operator ?= : (1/10)+/- 2019-12-07 16:13 6 years ago
[LanX]
Re^2: RFC: "assignary" operator ?= : (3/9)+/- 2019-12-07 16:34 6 years ago
Re^3: RFC: "assignary" operator ?= : (2/3)+/- 2019-12-07 16:49 6 years ago
[LanX]
Re^4: RFC: "assignary" operator ?= : (1)+/- 2019-12-07 17:38 6 years ago
[shmem]
Re^5: RFC: "assignary" operator ?= : 2019-12-07 18:01 6 years ago
[LanX]
Re^4: RFC: "assignary" operator ?= : 2019-12-07 22:13 6 years ago
Re^3: RFC: "assignary" operator ?= : (1/2)+/- 2019-12-07 17:03 6 years ago
[ikegami]
Re^4: RFC: "assignary" operator ?= : (1)+/- 2019-12-07 17:27 6 years ago
[Tux]
Re^5: RFC: "assignary" operator ?= : 2019-12-07 19:08 6 years ago
[ikegami]
Re^3: RFC: "assignary" operator ?= : (1)+/- 2019-12-08 00:55 6 years ago
[tobyink]
Re^4: RFC: "assignary" operator ?= : 2019-12-08 01:11 6 years ago
[LanX]
Re: RFC: "assignary" operator ?= : (1/15/3)+/- 2019-12-07 22:25 6 years ago
[shmem]
Re^2: RFC: "assignary" operator ?= : (1/14/3)+/- 2019-12-08 16:35 6 years ago
[LanX]
Re^3: RFC: "assignary" operator ?= : (2/13/3)+/- 2019-12-08 17:37 6 years ago
[shmem]
Re^4: RFC: "assignary" operator ?= : (1/10/3)+/- 2019-12-08 18:42 6 years ago
[LanX]
Re^5: RFC: "assignary" operator ?= : (2/9/3)+/- 2019-12-08 20:31 6 years ago
[shmem]
Re^6: RFC: "assignary" operator ?= : (compatibility) [5](1)+/- 2019-12-09 01:53 6 years ago
Re^7: RFC: "assignary" operator ?= : (compatibility) 2019-12-09 13:49 6 years ago
[tobyink]
Re^6: RFC: "assignary" operator ?= : (2/6/1)+/- 2019-12-09 22:32 6 years ago
Re^7: RFC: "assignary" operator ?= : 2019-12-09 23:49 6 years ago
[LanX]
Re^7: RFC: "assignary" operator ?= : (rareness) (2/4)+/- 2019-12-10 11:19 6 years ago
[shmem]
Re^8: RFC: "assignary" operator ?= : (rareness) (1/2)+/- 2019-12-10 11:58 6 years ago
[LanX]
Re^9: RFC: "assignary" operator ?= : (backward compatibility) (1)+/- 2019-12-10 13:18 6 years ago
[shmem]
Re^10: RFC: "assignary" operator ?= : (backward compatibility) 2019-12-10 13:38 6 years ago
[LanX]
Re^8: RFC: "assignary" operator ?= : (rareness) 2019-12-10 20:46 6 years ago
[ikegami]
Re^4: RFC: "assignary" operator ?= : (1)+/- 2019-12-08 20:49 6 years ago
[choroba]
Re^5: RFC: "assignary" operator ?= : 2019-12-08 21:03 6 years ago
[shmem]
Re: RFC: "assignary" operator ?= : (1)+/- 2019-12-08 21:47 6 years ago
[tobyink]
Re^2: RFC: "assignary" operator ?= : [6] 2019-12-09 02:18 6 years ago
Re: RFC: "assignary" operator ?= : ( conditional assignment , golf, death by diabetes ) [7](1/3)+/- 2019-12-09 02:13 6 years ago
Re^2: RFC: "assignary" operator ?= : ( conditional assignment , golf, death by diabetes ) (1/2)+/- 2019-12-09 13:24 6 years ago
Re^3: RFC: "assignary" operator ?= : ( conditional assignment , golf, death by diabetes ) (1)+/- 2019-12-09 19:36 6 years ago
[LanX]
Re^4: RFC: "assignary" operator ?= : ( conditional assignment , golf, death by diabetes ) 2019-12-09 21:24 6 years ago
Re: RFC: "assignary" operator ?= : (1)+/- 2019-12-09 05:53 6 years ago
[kcott]
Re^2: RFC: "assignary" operator ?= : [4] 2019-12-09 07:01 6 years ago
Re: RFC: "assignary" operator ?= : [-X](1/4)+/- 2019-12-10 03:57 6 years ago
Re^2: RFC: "assignary" operator ?= : (1/3)+/- 2019-12-10 06:59 6 years ago
Re: RFC: "assignary" operator ?= : ( source Filter::PPI::Transform ) [7](2/5)+/- 2019-12-11 06:29 6 years ago
Re^2: RFC: "assignary" operator ?= : ( source Filter::PPI::Transform ) (1/3)+/- 2019-12-11 11:44 6 years ago
[LanX]
Re^3: RFC: "assignary" operator ?= : ( source Filter::PPI::Transform ) (1/2)+/- 2019-12-11 13:32 6 years ago
[tobyink]
Re^4: RFC: "assignary" operator ?= : ( source Filter::PPI::Transform ) 2019-12-11 16:13 6 years ago
[LanX]
Re^2: RFC: "assignary" operator ?= : ( use Filter::PPI::Transform 'PPI::Transform::ConditionalAssignment'; ) [8] 2019-12-11 19:11 6 years ago
the star still shines (F:2/4/2)+/- 2019-12-07 22:02 6 years ago
[shmem]
Re: the star still shines (1)+/- 2019-12-08 12:25 6 years ago
[roho]
Re^2: the star still shines 2019-12-08 14:23 6 years ago
[shmem]
Re: the star still shines (1)+/- 2019-12-09 07:41 6 years ago
Re^2: the star still shines 2019-12-09 08:20 6 years ago
[shmem]